# What would Henry need to score on his fifth test to have an average of 86 if he had the following World History scores: 88, 76, 97, 84?

Nov 4, 2014
1. $\frac{X + 88 + 76 + 97 + 84}{5} = 86$

2. $\frac{X + 345}{5} = 86$

3. $\frac{X + 345}{5} \cdot 5 = 86 \cdot 5$

4. $X + 345 - 345 = 430 - 345$

5. $X = 85$

Checking:

$\frac{85 + 88 + 76 + 97 + 84}{5} = 86$ (correct)