# How to find the standard form of the equation of the specified circle given that it Is tangent to both axis and passes through ( 2 ,-1)?

##### 1 Answer

May 25, 2017

or

#### Explanation:

As the circle is tangent to both the axis, its centre is equidistant from both the axis

and as it passes through

or

and as it passes through

or

or

Hence

and equation of circle could be

graph{(x^2+y^2-10x+10y+25)(x^2+y^2-2x+2y+1)=0 [-1.793, 8.207, -3.94, 1.06]}