# How to find the x and y-intercept given y= 4x-2?

May 9, 2015

I_x ={x-intercept}={(1/2,0)}
I_y ={y-intercept}={(0,-2)}

The intercepts are made combining the equation of the two functions together

So, you know the equation of the $x$ axis is $y = 0$, and the equation of the $y$ axis is $x = 0$)
I_x={y=4x-2 & y=0},I_y={y=4x-2 & x=0}
so

${I}_{x} = \left\{\left(x , 0\right) : 4 x - 2 = 0\right\} = \left\{\left(\frac{1}{2} , 0\right)\right\}$
${I}_{y} = \left\{\left(0 , y\right) : y = 4 \cdot 0 - 2\right\} = \left\{\left(0 , - 2\right)\right\}$

graph{4x-2 [-10, 10, -5, 5]}