# How to find the zero's of #f(x)=1-x^3#?

##### 2 Answers

#### Explanation:

Using the difference of cubes formula

#=(1-x)(1^2+1*x+x^2)#

#=(1-x)(x^2+x+1)#

Now, setting this equal to

The first equation gives us

The second equation has no real solutions. We can see this by observing that the discriminant

#=-1/2+-sqrt(-3)/2#

Thus the only solution to

I propose a different method.

Solve for

Get rid of the cube:

Hence,

Hopefully this helps!