# How to graph a parabola y = (x + 2)^2 + 2?

Jun 5, 2015

$y = {\left(x + 2\right)}^{2} + 2$

The vertex of this parabola will be where $\left(x + 2\right) = 0$, that is where $x = - 2$ and $y = 0 + 2 = 2$, that is at $\left(- 2 , 2\right)$.

The axis is vertical, given by the equation $x = - 2$.

The intercept with the $y$ axis will be where $x = 0$, so

$y = {\left(0 + 2\right)}^{2} + 2 = 4 + 2 = 6$ - that is at $\left(0 , 6\right)$

$y \to \infty$ as $x \to \pm \infty$

If you want any more points, just substitute them into the equation of the parabola.

graph{(x+2)^2+2 [-11.87, 8.13, -1.68, 8.32]}