# How to write an equation in point-slope form, slope-intercept form, & and standard form for a line passing through (-2,-1) and parallel to the line whose equation is y-2=4/5(x-5)?

The line parallel would have the same slope, hence its point slope form would be y+1= $\frac{4}{5}$ (x+2).
Solving it for would give the point slope form y=$\frac{4}{5} x + \frac{3}{5}$