# How to write an equation in point-slope form, slope-intercept form, & and standard form for a line passing through (-2,-1) and parallel to the line whose equation is y-2=4/5(x-5)?

May 7, 2015

The line parallel would have the same slope, hence its point slope form would be y+1= $\frac{4}{5}$ (x+2).

Solving it for would give the point slope form y=$\frac{4}{5} x + \frac{3}{5}$

Simplifying the point slope form would give the standard form 4x-5y= -3