# How would you balance Ag2O --> Ag + O2?

Nov 18, 2015

$2 A {g}_{2} O \to 4 A g + {O}_{2}$

#### Explanation:

How to balance?
We have an equation;
$A {g}_{2} O \to A g + {O}_{2}$
First of all balance the O on both sides, now look at the product side. We have 2 oxygen on right side and on left side we have only 1 oxygen. To balance it, put a coefficient 2 on left side before $A {g}_{2} O$ . The equation becomes as
$2 A {g}_{2} O \to A g + {O}_{2}$
Now again check the product side, There is 1 Ag but in reactant side there is 4 Ag. Now put coefficient 4 before Ag on right side. The equation becomes as;
$2 A {g}_{2} O \to 4 A g + {O}_{2}$