Question

How would you convert `y=2sin(x-π)+5` into a cosine function?

Answer 1

`y=-2sqrt(1-cos^2x)+5`

Explanation:

We use the identities `sin(-A)=-sinA` and `sin(pi-A)=sinA`

As such `y=2sin(x-pi)+5`

`=2sin(-(pi-x))+5`

`=-2sin(pi-x)+5`

`=-2sinx+5`

`=-2sqrt(1-cos^2x)+5`