# How would you find the equation of the circle, Center (1,0) Radius =3?

Jan 6, 2016

${\left(x - 1\right)}^{2} + {y}^{2} = 9$

#### Explanation:

the standard form of the equation of a circle is :

${\left(x - a\right)}^{2} + {\left(y - b\right)}^{2} = {r}^{2}$

where (a , b ) is the centre and r = radius.

in this case (a , b ) = (1 , 0 ) and r=3

$\Rightarrow {\left(x - 1\right)}^{2} + {\left(y - 0\right)}^{2} = {3}^{2}$

$\Rightarrow {\left(x - 1\right)}^{2} + {y}^{2} = 9$