Question

How would you find the exact value of the six trigonometric function of 19pi/3?

Answer 1

Find trig function values

Explanation:

Use trig unit circle and trig table of special arcs -->
`sin ((19pi)/3) = sin (pi/3 + 6pi) = sin (pi/3) = sqrt3/2`
`cos ((19pi)/3) = cos (pi/3) = 1/2`
t`an ((19pi)/3) = sin/(cos) = sqrt3`
`cot ((19pi)/3) = 1/(tan) = 1/sqrt3 = sqrt3/3`
`sec ((19pi)/3) = 1/(cos) = 2`
`csc ((19pi)/3) = 1/(sin) = 2/sqrt3 = (2sqrt3)/3`