How would you prepare 250.0 mL of a 3.50 %m/v solution of #AgNO_3#?

1 Answer
Ernest Z.
Jul 12, 2016

You would dissolve 8.75 g of #"AgNO"_3# in enough water to make a total of 250.0 mL.

Explanation:

3.50 % m/v means that there are 3.50 g of solute in 100 mL of solution.

Thus,

#"Mass of AgNO"_3 = 250.0 color(red)(cancel(color(black)("mL solution"))) × ("3.50 g AgNO"_3)/(100 color(red)(cancel(color(black)("mL solution")))) = "8.75 g AgNO"_3#

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