# How would you prepare 250.0 mL of a 3.50 %m/v solution of AgNO_3?

Jul 12, 2016

You would dissolve 8.75 g of ${\text{AgNO}}_{3}$ in enough water to make a total of 250.0 mL.
${\text{Mass of AgNO"_3 = 250.0 color(red)(cancel(color(black)("mL solution"))) × ("3.50 g AgNO"_3)/(100 color(red)(cancel(color(black)("mL solution")))) = "8.75 g AgNO}}_{3}$