# How would you prepare 250. mL of a 0.175 M solution of Cobalt(II) Chloride from the solid and distilled water?

$250 \text{mL" * "L"/(10^3"mL") * 0.175"M" * (129.9"g")/"mol" approx 5.68"g}$
of cobalt (II) chloride in approximately $250 \text{mL}$ of distilled water to create the solution in the lab.