# How would you rank the following diatomic molecules from largest number of bonding electrons to smallest number of bonding electrons?

## chlorine, oxygen, carbon monoxide

Bond order reduces in the order, $C O$, ${O}_{2}$, and $C {l}_{2}$.
We formally invoke a triple bond in $: C \equiv O$, a double bond in $O = O$, and a single bond in $C l - C l$. Given these representations, there are $6$, $4$, and $2$ bonding electrons in each of the molecules.