How would you simplify #sqrt(12a^3b^4)#?

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Answer 1 · 2016-02-26T15:57:31

#= 2a bsqrt( 3 a b^2#

#sqrt( 12 * a^3 * b^4#

(note: #12# is prime factorised)

#= sqrt( color(blue)(2^2) * 3 * color(blue)(a^2) * a * color(blue)(b^2) * b^2#

#= color(blue)(2* a * b) sqrt( 3 * a * b^2#

#= 2a bsqrt( 3 * a * b^2#

How would you simplify #sqrt(12*a^3*b^4)#?