# How would you solve sqrt(x+10)=-3?

In the set of real numbers the equation $\sqrt{10 + x} = - 3$ has no solutions because the left part is always positive or equal to zero for $x = - 10$ and the right part is always negative.

If you see the graph of both functions $y = \sqrt{x + 10}$ (red line) and $y = - 3$ (blue line)
it is apparent that no real solutions exist.

Feb 27, 2016

x = -1

#### Explanation:

Well

$\sqrt{x + 10} = - 3$

Square both sides

$x + 10 = 9$

$x = - 1$
So

$\sqrt{9} = \pm 3$