How would you solve #sqrt(x+10)=-3#?

2 Answers

In the set of real numbers the equation #sqrt(10+x)=-3# has no solutions because the left part is always positive or equal to zero for #x=-10# and the right part is always negative.

If you see the graph of both functions #y=sqrt[x+10]# (red line) and #y=-3# (blue line)
it is apparent that no real solutions exist.

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Feb 27, 2016

Answer:

x = -1

Explanation:

Well

#sqrt(x+10) = -3#

Square both sides

#x +10= 9#

#x = -1#
So

#sqrt 9 = +-3#