# How would zero velocity and nonzero acceleration be represented on a velocity-time graph?

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My physics teacher did mention that with zero velocity and non-zero acceleration, the resulting motion would be "speeding up". I don't quite understand this comment as well as how to graph such motion on a velocity-time graph.

Thanks!

My physics teacher did mention that with zero velocity and non-zero acceleration, the resulting motion would be "speeding up". I don't quite understand this comment as well as how to graph such motion on a velocity-time graph.

Thanks!

##### 1 Answer

Dec 30, 2016

#### Answer:

Zero velocity and nonzero acceleration are two different cases.

#### Explanation:

- An object having zero velocity implies that it is stationary at a particular location. If we plot it on a velocity-time graph which represents velocity on the
#y# -axis and time on the#x# -axis, it is represented by#x# -axis

Value of#y# (velocity), is#0# for all values of#x# (time).

graph{y=0x [-2, 27.49, -2, 9.49]}

Represented by blue line in the figure above. - Nonzero acceleration, assuming it is constant. It could be either positive or negative. The general kinematic equation representing such a motion is
#v=u+at#

#v# is final velocity after time#t# ,#a# is the acceleration and#u# is the initial velocity.

Compare it with the equation of a straight line in the slope-intercept form

#y=mx+c#

We see that slope of the line represents acceleration.

As shown in the figure above, positive slope represents acceleration, (speeding up) from

Slope is negative from