How you you find the derivative #f(x)=x^2# using First Principles?
2 Answers
Apr 1, 2018
Explanation:
Apr 1, 2018
Explanation:
#f'(x)=lim_(hto0)(f(x+h)-f(x))/h#
#rArrf'(x)=lim_(hto0)((x+h)^2-x^2)/h#
#color(white)(rArrf'(x))=lim_(hto0)(cancel(x^2)+2hx+h^2cancel(-x^2))/h#
#color(white)(rArrf'(x))=lim_(hto0)(cancel(h)(2x+h))/cancel(h)#
#color(white)(rArrf'(x))=2x#