If 100 g of Au-198 decays to 6.25 g in 10.8 days, what is the half-life of Au-198?

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Dec 21, 2016

Answer:

Half life of 2.7 days

Explanation:

Since Au-198 is 100 g originally and it decays to 6.25 g,

You'd divide 100 g by 2 until you reach 6.25 g:

#100/2 = 50#; #50/2 = 25#; #25/2 = 12.5#; #12.5/2 = 6.25#

Since there were four 2s, divide 10.8 days by 4:

#"10.8 days"/4 = "2.7 days"#

100 g of Au-198 would have a half life of 2.7 days.

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