If #12 L# of a gas at room temperature exerts a pressure of #8 kPa# on its container, what pressure will the gas exert if the container's volume changes to #3 L#?

1 Answer
Jul 15, 2016

Answer:

The gas will exert a pressure of #color(blue)("32kPa").#

Explanation:

Let's identify our knowns and unknowns:

The first volume we have is #12# L, the first pressure is #8kPa#, and the second volume is #3L#. Our only unknown is the second pressure.

We can ascertain the answer using Boyle's Law:

annie-chemistry.blogspot.com

All we have to do is rearrange the equation to solve for #P_2#

We do this by dividing both sides by #V_2# in order to get #P_2# by itself:
#P_2=(P_1xxV_1)/V_2#

Now all we have to do is plug in the given values:
#P_2=(8\kPa xx 12\ cancel"L")/(3\cancel"L")# = #32 kPa#