# If 12 L of a gas at room temperature exerts a pressure of 9 kPa on its container, what pressure will the gas exert if the container's volume changes to 3 L?

Nov 10, 2016

The pressure is $= 36 k P a$
Use ${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$ (Boyle's law)
${P}_{1} = 9 k P a$
${V}_{1} = 12 l$
${V}_{2} = 3 l$
${P}_{2} = \frac{{P}_{1} {V}_{1}}{V} _ 2 = \frac{9 \cdot 12}{3} = 36 k P a$