If 15.0 g #CO_2# gas has a volume of 0.30 L at 300 K, of what is its pressure in millimeters of mercury?

1 Answer
Oct 15, 2016

Answer:

This is a high pressure system, whose pressure could not be reasonably measured in #"mm Hg"#. A pressure of #28.0*atm# would be developed given these parameters.

Explanation:

We work out the pressure in #"atmospheres"# for #(15.0*g)/(44.0*g*mol^-1)=0.341*mol# of an Ideal Gas.

#P=(nRT)/V# #=#

#(0.341*molxx0.0821*L*atm*K^-1*mol^-1xx300*K)/(0.30*L)#

#=# #28.0*atm#

I suspect that the question originally proposed a #0.15*g# mass of gas, which would lead to a pressure of less than an atmosphere, where a reading in #"mm Hg"# would be reasonable.