Question

If 15.0 g `CO_2` gas has a volume of 0.30 L at 300 K, of what is its pressure in millimeters of mercury?

Answer 1

This is a high pressure system, whose pressure could not be reasonably measured in `"mm Hg"`. A pressure of `28.0*atm` would be developed given these parameters.

Explanation:

We work out the pressure in `"atmospheres"` for `(15.0*g)/(44.0*g*mol^-1)=0.341*mol` of an Ideal Gas.

`P=(nRT)/V` `=`

`(0.341*molxx0.0821*L*atm*K^-1*mol^-1xx300*K)/(0.30*L)`

`=` `28.0*atm`

I suspect that the question originally proposed a `0.15*g` mass of gas, which would lead to a pressure of less than an atmosphere, where a reading in `"mm Hg"` would be reasonable.