# If 15 L of a gas at room temperature exerts a pressure of 5 kPa on its container, what pressure will the gas exert if the container's volume changes to 3 L?

Feb 22, 2017

The pressure is $= 25 k P a$

#### Explanation:

We apply Boyle's Law

${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

${P}_{1} = 5 k P a$

${V}_{1} = 15 L$

${V}_{1} = 3 L$

${P}_{2} = {V}_{1} / {V}_{2} \cdot {P}_{1}$

$= \frac{15}{3} \cdot 5 = 25 k P a$