If #17/6 L# of a gas at room temperature exerts a pressure of #24 kPa# on its container, what pressure will the gas exert if the container's volume changes to #5/4 L#?

1 Answer
Dec 25, 2016

Answer:

#54.4kPa#

Explanation:

We can obtain the final pressure via Boyle's Law:

http://slideplayer.com/slide/698879/

Let's identify the known and unknown variables:

#color(blue)("Knowns:")#
- Initial Volume
- Final Volume
- Initial Pressure

#color(magenta)("Unknowns:")#
- Final Pressure

All we have to do is rearrange the equation to solve for the final pressure. We do this by dividing both sides by #V_2# in order to get #P_2# by itself like this:
#P_2=(P_1xxV_1)/V_2#

Now all we do is plug in the values and we're done!

#P_2= (24kPa xx 17/6cancel"L")/(5/4\cancel"L")# = #54.4 kPa#