# If (-2, y) lies on the graph of y = 4^x, then what is y?

Jan 2, 2016

$y = \frac{1}{16}$

#### Explanation:

$\left(- 2 , y\right)$ is found through plugging in $- 2$ for $x$.

$y = {4}^{-} 2$

To find ${4}^{-} 2$, move the negative exponent to the denominator.

$y = \frac{1}{4} ^ 2$

$y = \frac{1}{16}$