If #3 L# of a gas at room temperature exerts a pressure of #15 kPa# on its container, what pressure will the gas exert if the container's volume changes to #5 L#?

1 Answer
Aug 3, 2016

Answer:

The gas will exert a pressure of # 9 kPa#

Explanation:

Let's begin by identifying our known and unknown variables.

The first volume we have is #3 L# , the first pressure is #15kPa# and the second volume is #5 L#. Our only unknown is the second pressure.

The answer can be determined by using Boyle's Law:
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Rearrange the equation to solve for the final pressure by dividing both sides by #V_2# to get #P_2# by itself like this:

#P_2=(P_1xxV_1)/V_2#

Plug in your given values to obtain the final pressure:

#P_2=(15\kPa xx 3\ cancel"L")/(5\cancel"L")# = #9kPa#