# If 3 L of a gas at room temperature exerts a pressure of 15 kPa on its container, what pressure will the gas exert if the container's volume changes to 5 L?

Aug 3, 2016

The gas will exert a pressure of $9 k P a$

#### Explanation:

Let's begin by identifying our known and unknown variables.

The first volume we have is $3 L$ , the first pressure is $15 k P a$ and the second volume is $5 L$. Our only unknown is the second pressure.

The answer can be determined by using Boyle's Law:

Rearrange the equation to solve for the final pressure by dividing both sides by ${V}_{2}$ to get ${P}_{2}$ by itself like this:

${P}_{2} = \frac{{P}_{1} \times {V}_{1}}{V} _ 2$

Plug in your given values to obtain the final pressure:

${P}_{2} = \left(15 \setminus k P a \times 3 \setminus \cancel{\text{L")/(5\cancel"L}}\right)$ = $9 k P a$