If #3 L# of a gas at room temperature exerts a pressure of #2 kPa# on its container, what pressure will the gas exert if it the container's volume changes to #1 L#?

1 Answer
Sep 9, 2016

Answer:

The gas will exert a pressure of #6kpa#

Explanation:

Let's identify the known and unknown variables:

#color(yellow)("Knowns:")#
- Initial Volume
- Final Volume
- Initial Pressure

#color(orange)("Unknowns:")#
- Final Pressure

We can obtain the answer using Boyle's Law:
www.physbot.co.uk

The letters i and f represent the initial and final conditions, respectively.

All we have to do is rearrange the equation to solve for the final pressure.

We do this by dividing both sides by #V_f# in order to get #P_f# by itself like this:
#P_f=(P_ixxV_i)/V_f#

Now all we do is plug in the values and we're done!

#P_f= (2kPa xx 3cancel"L")/(1\cancel"L")# = #6kPa#