If #8 L# of a gas at room temperature exerts a pressure of #45 kPa# on its container, what pressure will the gas exert if the container's volume changes to #9 L#?

1 Answer
Dec 27, 2016

Answer:

The gas will exert a pressure of 40 kPa.

Explanation:

We can obtain the final pressure via Boyle's Law:

http://slideplayer.com/slide/698879/

Let's identify the known and unknown variables:

#color(purple)("Knowns:")#
- Initial Volume
- Final Volume
- Initial Pressure

#color(green)("Unknowns:")#
- Final Pressure

All we have to do is rearrange the equation to solve for the final pressure. We do this by dividing both sides by #V_2# in order to get #P_2# by itself like this:
#P_2=(P_1xxV_1)/V_2#

Now all we do is plug in the values and we're done!

#P_2= (45kPa xx 8cancel"L")/(9\cancel"L")# = #40 kPa#