If #9 L# of a gas at room temperature exerts a pressure of #12 kPa# on its container, what pressure will the gas exert if the container's volume changes to #4 L#?

1 Answer
Jul 24, 2016

Answer:

#color(purple)("27 kpa"#

Explanation:

Let's identify our knowns and unknowns:

The first volume we have is #9 L#, the first pressure is #12kPa#, and the second volume is #4L#. Our only unknown is the second pressure.

We can ascertain the answer using Boyle's Law:
slideplayer.com

Rearrange the equation to solve for #P_2#

We do this by dividing both sides by #V_2# in order to get #P_2# by itself:
#P_2=(P_1xxV_1)/V_2#

Now all we have to do is plug in the given values:
#P_2=(12\kPa xx 9\ cancel"L")/(4\cancel"L")# = #27 kPa#