If a #1 kg# object moving at #1 m/s# slows down to a halt after moving #1 m#, what is the friction coefficient of the surface that the object was moving over?

1 Answer
May 19, 2017

Answer:

The coefficient of friction is #=0.051#

Explanation:

The coefficient of kinetic friction is #mu_k=F_r/N#

The normal force is #N=1gN#

Initial velocity is #u=1ms^-1#

Final velocity is #v=0ms^-1#

Distance is #s=1m#

We apply the equation of motion

#v^2=u^2+2as#

#0=1+2a#

#a=-1/2ms^-2#

The negative sign indicates that it is a deceleration.

According to Newton's Second Law,

#F=ma#

#F_r=1*1/2=1/2N#

Therefore,

#mu_k=(1/2)/(1g)=1/(2g)=0.051#