If a #3 kg# object moving at #9 m/s# slows down to a halt after moving #27 m#, what is the coefficient of kinetic friction of the surface that the object was moving over?
1 Answer
Explanation:
The work being done on the object is Work due to friction so the following equation is going to be used:
We can rewrite Equation (a) if we break down both sides step-by-step to become:
Since our object stopped, its final velocity becomes
Answer: 0.15