# If a #3 kg# object moving at #9 m/s# slows down to a halt after moving #27 m#, what is the coefficient of kinetic friction of the surface that the object was moving over?

##### 1 Answer

#### Answer:

#### Explanation:

The work being done on the object is **Work due to friction** so the following equation is going to be used:

**Equation (a)**

We can rewrite **Equation (a)** if we break down both sides step-by-step to become:

**Equation (b)**

Since our object stopped, its final velocity becomes

**Answer: 0.15**