If, A⊂B, Prove that B'⊂A' ?

If, A#sub# B,
Prove that B'#sub#A'

1 Answer
Jun 7, 2017

Please see below.

Explanation:

#A# is a set containing certain elements. How do we define #A'#?

Let us consider a universal set #U#, which is set of all the possible elements. Now as #A# contains some elements, #A'# is its complementary set which contains all the elements, other than those contained in #A#.

In other words #A subU#, #A'subU#, but #AuuA'=U# and #AnnA'=phi#. In other words #A# and #A'# together contain all the elements in the universal set #U#, but there is no element common between #A# and #A'#. In venn diagram we describe it as under:
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Now as #AsubB#, let #B# and #B'# be as shown below.
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Further as #AsubB#, we have #AnnB=A#

Comparing #A'# and #B'#, it is apparent that #A'# contains all the elements #B'# and additionally those as well which are contained in #B# but not #A#.

Hence #B'subA'#