# If a gas has an initial temperature of 300 K at a pressure of 100 kPa and it is then heated to 600 K, what is the new pressure?

Aug 26, 2016

The new pressure is $200 k P a$

#### Explanation:

This question requires you to use Gay-Lussac's law:

${P}_{1} / {T}_{1} = {P}_{2} / {T}_{2}$

The number 1 represents the initial conditions and the number 2 represents the final conditions.

Identify your known and unknown variables:

color(blue)("Knowns:"

${P}_{1}$= 100kPa
${T}_{1}$= 300K
${T}_{2}$ = 600K

color(magenta) ("Unknowns:"

${P}_{2}$

Rearrange the equation to solve ${P}_{2}$

${P}_{2} = \frac{{P}_{1} \times {T}_{2}}{T} _ 1$

Plug in your given values to obtain the final pressure:

${P}_{2} = \frac{100 k P a \times 600 \cancel{K}}{300 \cancel{K}}$ = $200 k P a$