If a gas has an initial temperature of 300 K at a pressure of 100 kPa and it is then heated to 600 K, what is the new pressure?

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Answer 1 · 2016-08-26T01:43:05

The new pressure is #200 kPa#

This question requires you to use Gay-Lussac's law:

#P_1/T_1 = P_2/T_2#

The number 1 represents the initial conditions and the number 2 represents the final conditions.

Identify your known and unknown variables:

#color(blue)("Knowns:"#

#P_1#= 100kPa
#T_1#= 300K
#T_2# = 600K

#color(magenta) ("Unknowns:"#

#P_2#

Rearrange the equation to solve #P_2#

#P_2=(P_1xxT_2)/T_1#

Plug in your given values to obtain the final pressure:

#P_2=(100 kPaxx600cancelK)/(300cancelK)# = #200 kPa#