If a maximum resistance produced by two resistors is #5 Omega# and minimum resistance produced by them is #1.2 Omega#, then what is the value of the resistances?

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Answer 1 · 2016-11-25T14:52:39

The maximum resistance is when the two resistances are in series, and the minimum when they are in parallel

#R_1+R_2 = 5 Omega#

#(R_1R_2)/(R_1+R_2) = 1.2Omega#

Solve the system and find:

#R_1 = 2Omega#
#R_1 = 3Omega#

Answer 2 · 2016-11-25T15:02:52

#r_1=2# and #r_2=3#

The maximun resistance is with both in series

#r_1+r_2= 5#

and the minimum is when in parallel

#1/r_1+1/r_2=1/1.2# so

#{(r_1+r_2= 5),((r_1+r_2)/(r_1r_2)=1/1.2):}#

or

#{(r_1+r_2= 5),(r_1r_2=1.2 xx 5):}# giving

#r_1=2# and #r_2=3#