If a maximum resistance produced by two resistors is $5 Omega$ and minimum resistance produced by them is $1.2 Omega$ , then what is the value of the resistances?

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Answer 1 · 2016-11-25T14:52:39

The maximum resistance is when the two resistances are in series, and the minimum when they are in parallel

$R_1+R_2 = 5 Omega$

$(R_1R_2)/(R_1+R_2) = 1.2Omega$

Solve the system and find:

$R_1 = 2Omega$
$R_1 = 3Omega$

Answer 2 · 2016-11-25T15:02:52

$r_1=2$ and $r_2=3$

The maximun resistance is with both in series

$r_1+r_2= 5$

and the minimum is when in parallel

$1/r_1+1/r_2=1/1.2$ so

${(r_1+r_2= 5),((r_1+r_2)/(r_1r_2)=1/1.2):}$

or

${(r_1+r_2= 5),(r_1r_2=1.2 xx 5):}$ giving

$r_1=2$ and $r_2=3$

If a maximum resistance produced by two resistors is 5 Omega5 Omega and minimum resistance produced by them is 1.2 Omega1.2 Omega, then what is the value of the resistances?