If a net force of 25 N is exerted over a distance of 4 m on a 2 kg mass object and moves it, what is the final velocity?

1 Answer
Oct 17, 2015

Answer:

#10m//s#

Explanation:

From Newton's 2nd Law of Motion,
#sumvec F = m vec a#

Hence the acceleration of the object under this constant resultant force is
#a=(sumF)/m=25/2=12,5m//s^2#

Now assuming the object started from rest, we may use an equation of motion for constant linear acceleration to get the final velocity :

#v^2=u^2+2ax#

#therefore v=sqrt(0^2+2xx12,5xx4)=10m//s#