# If a net force of 25 N is exerted over a distance of 4 m on a 2 kg mass object and moves it, what is the final velocity?

Oct 17, 2015

#### Answer:

$10 m / s$

#### Explanation:

From Newton's 2nd Law of Motion,
$\sum \vec{F} = m \vec{a}$

Hence the acceleration of the object under this constant resultant force is
$a = \frac{\sum F}{m} = \frac{25}{2} = 12 , 5 m / {s}^{2}$

Now assuming the object started from rest, we may use an equation of motion for constant linear acceleration to get the final velocity :

${v}^{2} = {u}^{2} + 2 a x$

$\therefore v = \sqrt{{0}^{2} + 2 \times 12 , 5 \times 4} = 10 m / s$