If a projectile is shot at an angle of #(2pi)/3# and at a velocity of #1 m/s#, when will it reach its maximum height?
1 Answer
Jul 21, 2017
Answer:
Explanation:
We're asked to find the time
To do this, we can use the equation
where

#v_y# is the velocity at time#t# (this will be#0# , since at a particle's maximum height its instantaneous#y# velocity is#0# ) 
#v_0# is the initial speed (give as#1# #"m/s"# ) 
#alpha_0# is the launch angle (given as#(2pi)/3# ) 
#g# is the acceleration due to gravity near earth's surface (#9.81# #"m/s"^2# ) 
#t# is the time (what we're trying to find)
Plugging in known values, we have