If a projectile is shot at an angle of (2pi)/3 and at a velocity of 5 m/s, when will it reach its maximum height?
1 Answer
Feb 22, 2018
time taken to reach maximum height =
Explanation:
The velocity vector of the projectile has a x- component and y - component .
since we are dealing with height , we just need the y-component .
velocity in
=
now using initial velocity
final velocity
we have