If a projectile is shot at an angle of #(2pi)/3# and at a velocity of #6 m/s#, when will it reach its maximum height?
The projectile will reach its maximum height at 0.53 s
We consider the equation
we find the moment when the horizontal component of speed is 0 (the vertical component is v(x)=vsin(a))
so we have the equation
a is equal to g, so