# If a projectile is shot at an angle of (2pi)/3 and at a velocity of 6 m/s, when will it reach its maximum height?

Dec 27, 2015

$s = v t - \frac{1}{2} a {t}^{2}$ and $v = v - a t$
so we have the equation $v - a t = 0$
a is equal to g, so $t = \frac{v}{g} = 0.53 \frac{m}{s} ^ 2$