If a projectile is shot at an angle of (2pi)/32π3 and at a velocity of 6 m/s6ms, when will it reach its maximum height?
1 Answer
Dec 27, 2015
The projectile will reach its maximum height at 0.53 s
Explanation:
We consider the equation
we find the moment when the horizontal component of speed is 0 (the vertical component is v(x)=vsin(a))
so we have the equation
a is equal to g, so