Question

If a projectile is shot at an angle of `(3pi)/8` and at a velocity of `8 m/s`, when will it reach its maximum height?

Answer 1

`t~=0,41 s`

Explanation:

`t=v_i*sin alpha/g`
`alpha=3pi/18*180/pi=30^o" "sin 30=0,5`
`t=(8*0,5)/(9,81)`