Question

If a projectile is shot at an angle of `(5pi)/12` and at a velocity of `16 m/s`, when will it reach its maximum height??

Answer 1

1.545 seconds

Explanation:

`T = (u sin θ) / g`

`T = (16 ms^-1 sin ((5 π)/12)) / (10 ms^-2)`

`T = (16 × 0.9659) / (10)` s

`T = 1.545` `text(seconds)`