# If a projectile is shot at an angle of (5pi)/12 and at a velocity of 16 m/s, when will it reach its maximum height??

Oct 12, 2017

1.545 seconds

#### Explanation:

T = (u sin θ) / g

T = (16 ms^-1 sin ((5 π)/12)) / (10 ms^-2)

T = (16 × 0.9659) / (10) s

$T = 1.545$ $\textrm{\sec o n \mathrm{ds}}$