If a projectile is shot at an angle of #(5pi)/12# and at a velocity of #19 m/s#, when will it reach its maximum height??

1 Answer
Apr 1, 2017

Answer:

The projectile will reach its maximum height when the velocity equals zero.

Explanation:

At an angle of #((5pi)/12)#, the initial velocity forms the hypotenuse of a right-angled triangle with angle #((5pi)/12)# at the base.
The maximum height of the shot will be the vertical component #(y)#, of the initial velocity vector of #19# m/s, and will occur when the final velocity equals zero.
The initial velocity of the vertical component is #Voy = 19sin((5pi)/12) = 0.434# m/s.
Using # V = Vo + at# we can rearrange to find #t#:

#t = (V - Vo)/a#

# = (0 - 0.434)/- 9.8 = 0.04 s#

Assuming that the force due to gravity is in the downward direction, therefore, the upward direction has a negative sign.