Question

If a projectile is shot at an angle of `(5pi)/12` and at a velocity of `6 m/s`, when will it reach its maximum height??

Answer 1

`t_e~=0,59 s`

Explanation:

`"you can find the elapsed time to maximum height by: "`
`t_e=v_i*sin alpha /g`
`v_i:"initial velocity of object"`
`alpha:"angle of projectile :" alpha=(5pi)/12*180/pi=75^o`
`g:"acceleration of gravity"`
`t_e=(6*sin 75)/(9,81)`
`t_e~=0,59 s`