Question

If a projectile is shot at an angle of `(7pi)/12` and at a velocity of `1 m/s`, when will it reach its maximum height?

Answer 1

`t_e=0,098 s`

Explanation:

`alpha=7pi/12`
`v_i=1 m/s`
`t_e=v_i*sin alpha/g" elapsed time to the maximum height"`
`t_e=(1*sin(7pi/12))/(9,81)`
`t_e=0,098 s`