If a projectile is shot at an angle of $\frac{7 π}{12}$ $(7pi)/12$ and at a velocity of $21 \frac{m}{s}$ $21 m/s$ , when will it reach its maximum height??

Question

1474 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-30T19:31:14

At the maxima of a projectile's parabolic trajectory, $ν_{y} = 0$ $nu_y = 0$ .

Given,

$ν_{y 0} = ν sin (θ) = \frac{20.2 m}{s}$ $nu_(y0) = nusin(theta) = (20.2"m")/"s"$
$ν_{y} = 0$ $nu_"y" = 0$
$a_{y} = g$ $a_y = g$

Recall,

$ν = ν_{0} + a t$ $nu = nu_0 + at$

Hence, it will take,

$=> t = (Deltanu)/a approx 2.07"s"$

for the projectile to reach its maximum height.

If a projectile is shot at an angle of (7pi)/127π12(7pi)/12 and at a velocity of 21 m/s21ms21 m/s, when will it reach its maximum height??