# If a projectile is shot at an angle of pi/12 and at a velocity of 1 m/s, when will it reach its maximum height??

Dec 2, 2016

The maximum height is $= 0.013 m$

#### Explanation:

The maximum height is given by

${h}_{\max} = \frac{{v}_{0}^{2} {\sin}^{2} \theta}{2 g}$

${v}_{0} = 1 m {s}^{- 1}$

$\theta = \frac{\pi}{12}$

$g = 10 m {s}^{- 2}$

So,

${h}_{\max} = 1 \cdot {\sin}^{2} \frac{\frac{\pi}{12}}{2 \cdot 10}$

$= 0.013 m$