# If a projectile is shot at an angle of pi/12 and at a velocity of 14 m/s, when will it reach its maximum height??

##### 1 Answer
Jan 23, 2018

$0.36 s$

#### Explanation:

Clearly,here the projectile will go upwards due to its vertical component of velocity,which is $14 \sin \left(\frac{\pi}{12}\right)$ i.e $3.62 \frac{m}{s}$ (considering the given angle was w.r.t the ground)

So,now we can use $v = u - a t$ (all the symbols are bearing their conventional meaning)

Here,$v = 0 , u = 3.62 , a = g$ and $t$ is the time in which it will reach the highest point.

So,we get,$t = 0.36 s$