If a projectile is shot at an angle of #pi/12# and at a velocity of #14 m/s#, when will it reach its maximum height??

1 Answer
Jan 23, 2018

Answer:

#0.36 s#

Explanation:

Clearly,here the projectile will go upwards due to its vertical component of velocity,which is #14 sin (pi/12)# i.e #3.62 m/s# (considering the given angle was w.r.t the ground)

So,now we can use #v=u-at# (all the symbols are bearing their conventional meaning)

Here,#v=0,u=3.62 ,a=g# and #t# is the time in which it will reach the highest point.

So,we get,#t=0.36 s#