If a projectile is shot at an angle of π12 and at a velocity of 14ms, when will it reach its maximum height??

1 Answer
Jan 23, 2018

0.36s

Explanation:

Clearly,here the projectile will go upwards due to its vertical component of velocity,which is 14sin(π12) i.e 3.62ms (considering the given angle was w.r.t the ground)

So,now we can use v=uat (all the symbols are bearing their conventional meaning)

Here,v=0,u=3.62,a=g and t is the time in which it will reach the highest point.

So,we get,t=0.36s