If a projectile is shot at an angle of pi/12 and at a velocity of 22 m/s, when will it reach its maximum height??

1 Answer
Jan 31, 2018

0.57 s

Explanation:

here,the projectile will go up due to the vertical component of its velocity, i.e 22 sin (pi/12) or, 5.7 m/s

So,it will reach the highest point,when its upward velocity becomes zero,

so,we can apply v=u-g t

So,for v=0, t= 5.7/10 s or,0.57 s