Question

If a projectile is shot at an angle of `pi/12` and at a velocity of `22 m/s`, when will it reach its maximum height??

Answer 1

`0.57 s`

Explanation:

here,the projectile will go up due to the vertical component of its velocity, i.e `22 sin (pi/12)` or, `5.7 m/s`

So,it will reach the highest point,when its upward velocity becomes zero,

so,we can apply `v=u-g t`

So,for `v=0`, `t= 5.7/10 s` or,`0.57 s`