# If a projectile is shot at an angle of pi/12 and at a velocity of 24 m/s, when will it reach its maximum height??

Mar 6, 2016

$t \cong 0 , 63 s$

#### Explanation:

$g \cdot t = {v}_{i} \cdot \sin \alpha$
$t = \frac{{v}_{i} \cdot \sin \alpha}{g}$
$\alpha = \frac{\pi}{12} \cdot \frac{180}{\pi} = 15$
$t = 24 \cdot \sin \frac{15}{9 , 81}$
$t \cong 0 , 63 s$