# If a projectile is shot at an angle of pi/2 and at a velocity of 31 m/s, when will it reach its maximum height??

Jun 7, 2018

$\text{3.2 s}$

#### Explanation:

Time taken to reach maximum height is given by

$\text{T" = "usinθ"/"g}$

color(white)("T") = "31 m/s × sin(π/2)"/"9.8 m/s"^2

color(white)("T") = 3.2\ "s"