Question

If a projectile is shot at an angle of `pi/3` and at a velocity of `1m/s`, when will it reach its maximum height??

Answer 1

After `0.088"s"`

Explanation:

Use the equation of motion

`v=u+at`

The vertical component of velocity is given by:

`v_y=vsintheta`

So the equation becomes:

`0=vsintheta-"g"t`

`:.t=(vsintheta)/g`

`theta=pi/3=60^@`

`:.t=1xxsin60/9.8=0.866/9.8=0.088"s"`