# If a projectile is shot at an angle of pi/3 and at a velocity of 2 m/s, when will it reach its maximum height??

Feb 17, 2016

$t \cong 0 , 18 s$
$\alpha = \frac{\pi}{3} \cdot \frac{180}{\pi} = {60}^{o}$
$t = {v}_{i} \cdot \sin \frac{\alpha}{g}$
$t = 2 \cdot \sin \frac{60}{9 , 81}$
$t = \frac{2 \cdot 0 , 866}{9 , 81}$
$t \cong 0 , 18 s$