Question

If a projectile is shot at an angle of `pi/3` and at a velocity of `2 m/s`, when will it reach its maximum height??

Answer 1

`t~=0,18 s`

Explanation:

`alpha=pi/3*180/pi=60^o`
`t=v_i*sin alpha/g`
`t=2*sin 60/(9,81)`
`t=(2*0,866)/(9,81)`
`t~=0,18 s`